Resolver [(1/3)^-3+(2/5)^-2+(4/23)^-1+10]^frac{1{2}}

$$[ ( \frac { 1 } { 3 } ) ^ { - 3 } + ( \frac { 2 } { 5 } ) ^ { - 2 } + ( \frac { 4 } { 23 } ) ^ { - 1 } + 10 ] ^ { \frac { 1 } { 2 } }$$

Avaliar

$$7$$

Passos Para a Resolução

Calcule \frac{1}{3} elevado a -3 e obtenha 27.

$$\left(27+\left(\frac{2}{5}\right)^{-2}+\left(\frac{4}{23}\right)^{-1}+10\right)^{\frac{1}{2}}$$

Calcule \frac{2}{5} elevado a -2 e obtenha \frac{25}{4}.

$$\left(27+\frac{25}{4}+\left(\frac{4}{23}\right)^{-1}+10\right)^{\frac{1}{2}}$$

Some 27 e \frac{25}{4} para obter \frac{133}{4}.

$$\left(\frac{133}{4}+\left(\frac{4}{23}\right)^{-1}+10\right)^{\frac{1}{2}}$$

Calcule \frac{4}{23} elevado a -1 e obtenha \frac{23}{4}.

$$\left(\frac{133}{4}+\frac{23}{4}+10\right)^{\frac{1}{2}}$$

Some \frac{133}{4} e \frac{23}{4} para obter 39.

$$\left(39+10\right)^{\frac{1}{2}}$$

Some 39 e 10 para obter 49.

$$49^{\frac{1}{2}}$$

Calcule 49 elevado a \frac{1}{2} e obtenha 7.

$$7$$

Fatorizar

$$7$$