Rozwiąż sin(x)=1 | Microsoft Math Solver

Rozwiąż względem x

x = 2 π n_{1} + \frac{π}{2}

n_{1} \in Z

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Quiz

5 działań(-nia) podobnych(-ne) do:

sin (x) = 1

Podobne zadania z wyszukiwania w sieci web

Particular integral for

x sin (1 - x)

https://math.stackexchange.com/questions/1265354/particular-integral-for-x-sin1-x

Try splitting up

sin (1 - x)

using the difference formula for

sin

sin (α \pm β) = sin α cos β \pm cos α sin β

This should tell you what your particular ...

Limits of the solutions to

x sin x = 1

https://math.stackexchange.com/questions/719244/limits-of-the-solutions-to-x-sin-x-1

Because you are always evaluating the limit, this is an asymptotic expansion of the explicit expression for the solutions. Write

x = 2 π n + ϵ

sin ϵ = \frac{1}{2 π n + ϵ}

How to determine the solution to

sin x = 8

in the complex numbers

https://www.quora.com/How-do-you-determine-the-solution-to-sin-x-8-in-the-complex-numbers

Let’s just solve the general

sin x = t

t = 8 .

e^{i x} = cos x + i sin x

e^{- i x} = cos x - i sin x

e^{i x} - e^{- i x} = 2 i sin x

sin x = \frac{e ^{i x} - e ^{- i x}}{2 i}

Find the critical points of:

y = x + cos (x)

https://math.stackexchange.com/q/124497

You're essentially there:

y = x + cos (x) = \frac{π}{2} + 2 π k + cos (\frac{π}{2} + 2 π k) = \frac{π}{2} + 2 π k

. There are infinitely many

y

-values, one for each

k \in Z

cos 2 x - sin x = 0

0 \leq x \leq 360

https://math.stackexchange.com/questions/1778416/solve-cos-2x-sin-x-0-for-0-le-x-le-360

2 sin x = 1

, you should have

sin x = 0.5

. Sine is positive in the first two quadrants, you should obtain

3 0^{\circ}

15 0^{\circ}

as your solution as well.

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Przykłady

Równanie kwadratowe

x^{2} - 4 x - 5 = 0

4 sin θ cos θ = 2 sin θ

Równanie liniowe

y = 3 x + 4

699 * 533

[2534] [2 - 1 0135]

Równania równoważne

{8 x + 2 y = 46 7 x + 3 y = 47

Różniczkowanie

\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

\int_{0}^{1} x e^{- x^{2}} d x

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}