y=3/sqrt{3-x^2}quadDelta:3 ਨੂੰ ਹੱਲ ਕਰੋ

$$y = \frac { 3 } { \sqrt { 3 - x ^ { 2 } } } \quad \Delta : 3$$

x ਲਈ ਹਲ ਕਰੋ (ਜਟਿਲ ਹੱਲ)

$$\left\{\begin{matrix}x=-\sqrt{-\left(\frac{\Delta }{y}\right)^{2}+3}\text{; }x=\sqrt{-\left(\frac{\Delta }{y}\right)^{2}+3}\text{, }&|arg(\sqrt{\left(\frac{\Delta }{y}\right)^{2}}y)-arg(\Delta )|<\pi \text{ and }\Delta \neq 0\text{ and }y\neq 0\\x\in \mathrm{C}\setminus -\sqrt{3},\sqrt{3}\text{, }&y=0\text{ and }\Delta =0\end{matrix}\right.$$

y ਲਈ ਹਲ ਕਰੋ (ਜਟਿਲ ਹੱਲ)

$$y=\left(3-x^{2}\right)^{-\frac{1}{2}}\Delta$$

$$x\neq -\sqrt{3}\text{ and }x\neq \sqrt{3}$$

x ਲਈ ਹਲ ਕਰੋ

$$\left\{\begin{matrix}x=\frac{\sqrt{3y^{2}-\Delta ^{2}}}{|y|}\text{; }x=-\frac{\sqrt{3y^{2}-\Delta ^{2}}}{|y|}\text{, }&\left(y\geq \frac{\sqrt{3}\Delta }{3}\text{ and }\Delta >0\right)\text{ or }\left(y\leq \frac{\sqrt{3}\Delta }{3}\text{ and }\Delta <0\right)\\x\in \left(-\sqrt{3},\sqrt{3}\right)\text{, }&y=0\text{ and }\Delta =0\end{matrix}\right.$$

y ਲਈ ਹਲ ਕਰੋ

$$y=\frac{\Delta }{\sqrt{3-x^{2}}}$$

$$|x|<\sqrt{3}$$