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x \sqrt{40} + 3 \cdot 0.9975640502598242 = 70
Evaluate trigonometric functions in the problem
x\times 2\sqrt{10}+3\times 0.9975640502598242=70
Iffattura 40=2^{2}\times 10. Erġa' ikteb l-għerq kwadrat tal-prodott \sqrt{2^{2}\times 10} bħala l-prodott tal-għeruq kwadrati \sqrt{2^{2}}\sqrt{10}. Ħu l-għerq kwadrat ta' 2^{2}.
x\times 2\sqrt{10}+2.9926921507794726=70
Immultiplika 3 u 0.9975640502598242 biex tikseb 2.9926921507794726.
x\times 2\sqrt{10}=70-2.9926921507794726
Naqqas 2.9926921507794726 miż-żewġ naħat.
x\times 2\sqrt{10}=67.0073078492205274
Naqqas 2.9926921507794726 minn 70 biex tikseb 67.0073078492205274.
2\sqrt{10}x=67.0073078492205274
L-ekwazzjoni hija f'forma standard.
\frac{2\sqrt{10}x}{2\sqrt{10}}=\frac{67.0073078492205274}{2\sqrt{10}}
Iddividi ż-żewġ naħat b'2\sqrt{10}.
x=\frac{67.0073078492205274}{2\sqrt{10}}
Meta tiddividi b'2\sqrt{10} titneħħa l-multiplikazzjoni b'2\sqrt{10}.
x=\frac{335036539246102637\sqrt{10}}{100000000000000000}
Iddividi 67.0073078492205274 b'2\sqrt{10}.