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Solvi għal S
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Solvi għal a
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Problemi Simili mit-Tiftix tal-Web

Sehem

\sqrt{6-\sqrt{35}}-\sqrt{6+\sqrt{35}}S=a
Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.
-\sqrt{6+\sqrt{35}}S=a-\sqrt{6-\sqrt{35}}
Naqqas \sqrt{6-\sqrt{35}} miż-żewġ naħat.
\left(-\sqrt{\sqrt{35}+6}\right)S=a-\sqrt{6-\sqrt{35}}
L-ekwazzjoni hija f'forma standard.
\frac{\left(-\sqrt{\sqrt{35}+6}\right)S}{-\sqrt{\sqrt{35}+6}}=\frac{a+\frac{\sqrt{10}}{2}-\frac{\sqrt{14}}{2}}{-\sqrt{\sqrt{35}+6}}
Iddividi ż-żewġ naħat b'-\sqrt{6+\sqrt{35}}.
S=\frac{a+\frac{\sqrt{10}}{2}-\frac{\sqrt{14}}{2}}{-\sqrt{\sqrt{35}+6}}
Meta tiddividi b'-\sqrt{6+\sqrt{35}} titneħħa l-multiplikazzjoni b'-\sqrt{6+\sqrt{35}}.
S=-\frac{\frac{\sqrt{14}-\sqrt{10}}{2}\left(2a+\sqrt{10}-\sqrt{14}\right)}{2}
Iddividi a-\frac{\sqrt{14}}{2}+\frac{\sqrt{10}}{2} b'-\sqrt{6+\sqrt{35}}.
a=-\sqrt{\sqrt{35}+6}S+\sqrt{-\sqrt{35}+6}
Erġa' ordna t-termini.