Issolvi 80+40sqrt{2}=5+5+5sqrt{2}*x

$$80+40 \sqrt{ 2 } =5+5+5 \sqrt{ 2 } \times x$$

Solvi għal x

$$x=7\sqrt{2}+8\approx 17.899494937$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Żid 5 u 5 biex tikseb 10.

$$80+40\sqrt{2}=10+5\sqrt{2}x$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$10+5\sqrt{2}x=80+40\sqrt{2}$$

Naqqas 10 miż-żewġ naħat.

$$5\sqrt{2}x=80+40\sqrt{2}-10$$

Naqqas 10 minn 80 biex tikseb 70.

$$5\sqrt{2}x=70+40\sqrt{2}$$

L-ekwazzjoni hija f'forma standard.

$$5\sqrt{2}x=40\sqrt{2}+70$$

Iddividi ż-żewġ naħat b'5\sqrt{2}.

$$\frac{5\sqrt{2}x}{5\sqrt{2}}=\frac{40\sqrt{2}+70}{5\sqrt{2}}$$

Meta tiddividi b'5\sqrt{2} titneħħa l-multiplikazzjoni b'5\sqrt{2}.

$$x=\frac{40\sqrt{2}+70}{5\sqrt{2}}$$

Iddividi 70+40\sqrt{2} b'5\sqrt{2}.

$$x=7\sqrt{2}+8$$