Issolvi 5a(x+2)+3(x+a)=4(x+3a)-5(1-ax)

$$5 a ( x + 2 ) + 3 ( x + a ) = 4 ( x + 3 a ) - 5 ( 1 - a x )$$

Solvi għal a

$$a=x-5$$

Passi tas-Soluzzjonijiet

Uża l-propjetà distributtiva biex timmultiplika 5a b'x+2.

$$5ax+10a+3\left(x+a\right)=4\left(x+3a\right)-5\left(1-ax\right)$$

Uża l-propjetà distributtiva biex timmultiplika 3 b'x+a.

$$5ax+10a+3x+3a=4\left(x+3a\right)-5\left(1-ax\right)$$

Ikkombina 10a u 3a biex tikseb 13a.

$$5ax+13a+3x=4\left(x+3a\right)-5\left(1-ax\right)$$

Uża l-propjetà distributtiva biex timmultiplika 4 b'x+3a.

$$5ax+13a+3x=4x+12a-5\left(1-ax\right)$$

Uża l-propjetà distributtiva biex timmultiplika -5 b'1-ax.

$$5ax+13a+3x=4x+12a-5+5ax$$

Naqqas 12a miż-żewġ naħat.

$$5ax+13a+3x-12a=4x-5+5ax$$

Ikkombina 13a u -12a biex tikseb a.

$$5ax+a+3x=4x-5+5ax$$

Naqqas 5ax miż-żewġ naħat.

$$5ax+a+3x-5ax=4x-5$$

Ikkombina 5ax u -5ax biex tikseb 0.

$$a+3x=4x-5$$

Naqqas 3x miż-żewġ naħat.

$$a=4x-5-3x$$

Ikkombina 4x u -3x biex tikseb x.

$$a=x-5$$

Solvi għal x

$$x=a+5$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 5a b'x+2.

$$5ax+10a+3\left(x+a\right)=4\left(x+3a\right)-5\left(1-ax\right)$$

Uża l-propjetà distributtiva biex timmultiplika 3 b'x+a.

$$5ax+10a+3x+3a=4\left(x+3a\right)-5\left(1-ax\right)$$

Ikkombina 10a u 3a biex tikseb 13a.

$$5ax+13a+3x=4\left(x+3a\right)-5\left(1-ax\right)$$

Uża l-propjetà distributtiva biex timmultiplika 4 b'x+3a.

$$5ax+13a+3x=4x+12a-5\left(1-ax\right)$$

Uża l-propjetà distributtiva biex timmultiplika -5 b'1-ax.

$$5ax+13a+3x=4x+12a-5+5xa$$

Naqqas 4x miż-żewġ naħat.

$$5ax+13a+3x-4x=12a-5+5xa$$

Ikkombina 3x u -4x biex tikseb -x.

$$5ax+13a-x=12a-5+5xa$$

Naqqas 5xa miż-żewġ naħat.

$$5ax+13a-x-5xa=12a-5$$

Ikkombina 5ax u -5xa biex tikseb 0.

$$13a-x=12a-5$$

Naqqas 13a miż-żewġ naħat.

$$-x=12a-5-13a$$

Ikkombina 12a u -13a biex tikseb -a.

$$-x=-a-5$$

Iddividi ż-żewġ naħat b'-1.

$$\frac{-x}{-1}=\frac{-a-5}{-1}$$

Meta tiddividi b'-1 titneħħa l-multiplikazzjoni b'-1.

$$x=\frac{-a-5}{-1}$$

Iddividi -a-5 b'-1.

$$x=a+5$$