Issolvi 40sqrt{6}*frac{sqrt{6}+sqrt{2}}{4}

$$40 \sqrt { 6 } \times \frac { \sqrt { 6 } + \sqrt { 2 } } { 4 }$$

Evalwa

$$20\sqrt{3}+60\approx 94.641016151$$

Passi tas-Soluzzjonijiet

Ikkanċella l-akbar fattur komuni 4 f'40 u 4.

$$10\left(\sqrt{6}+\sqrt{2}\right)\sqrt{6}$$

Uża l-propjetà distributtiva biex timmultiplika 10 b'\sqrt{6}+\sqrt{2}.

$$\left(10\sqrt{6}+10\sqrt{2}\right)\sqrt{6}$$

Uża l-propjetà distributtiva biex timmultiplika 10\sqrt{6}+10\sqrt{2} b'\sqrt{6}.

$$10\left(\sqrt{6}\right)^{2}+10\sqrt{2}\sqrt{6}$$

Il-kwadrat ta' \sqrt{6} huwa 6.

$$10\times 6+10\sqrt{2}\sqrt{6}$$

Immultiplika 10 u 6 biex tikseb 60.

$$60+10\sqrt{2}\sqrt{6}$$

Iffattura 6=2\times 3. Erġa' ikteb l-għerq kwadrat tal-prodott \sqrt{2\times 3} bħala l-prodott tal-għeruq kwadrati \sqrt{2}\sqrt{3}.

$$60+10\sqrt{2}\sqrt{2}\sqrt{3}$$

Immultiplika \sqrt{2} u \sqrt{2} biex tikseb 2.

$$60+10\times 2\sqrt{3}$$

Immultiplika 10 u 2 biex tikseb 20.

$$60+20\sqrt{3}$$