Issolvi 34(x-1)-12(2x-2)=7(05-x)+2(225+3x)

$$34(x-1)-12(2x-2)=7(05-x)+2(225+3x)$$

Solvi għal x

$$x = \frac{460}{11} = 41\frac{9}{11} \approx 41.818181818$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 34 b'x-1.

$$34x-34-12\left(2x-2\right)=7\left(0\times 5-x\right)+2\left(225+3x\right)$$

Uża l-propjetà distributtiva biex timmultiplika -12 b'2x-2.

$$34x-34-24x+24=7\left(0\times 5-x\right)+2\left(225+3x\right)$$

Ikkombina 34x u -24x biex tikseb 10x.

$$10x-34+24=7\left(0\times 5-x\right)+2\left(225+3x\right)$$

Żid -34 u 24 biex tikseb -10.

$$10x-10=7\left(0\times 5-x\right)+2\left(225+3x\right)$$

Immultiplika 0 u 5 biex tikseb 0.

$$10x-10=7\left(0-x\right)+2\left(225+3x\right)$$

Xi ħaġa plus żero jirriżulta f'dan in-numru stess.

$$10x-10=7\left(-1\right)x+2\left(225+3x\right)$$

Immultiplika 7 u -1 biex tikseb -7.

$$10x-10=-7x+2\left(225+3x\right)$$

Uża l-propjetà distributtiva biex timmultiplika 2 b'225+3x.

$$10x-10=-7x+450+6x$$

Ikkombina -7x u 6x biex tikseb -x.

$$10x-10=-x+450$$

Żid x maż-żewġ naħat.

$$10x-10+x=450$$

Ikkombina 10x u x biex tikseb 11x.

$$11x-10=450$$

Żid 10 maż-żewġ naħat.

$$11x=450+10$$

Żid 450 u 10 biex tikseb 460.

$$11x=460$$

Iddividi ż-żewġ naħat b'11.

$$x=\frac{460}{11}$$