Issolvi 0.18x+0.9436=0.7(x+0.62)

$$0.18 x + 0.9436 = 0.7 ( x + 0.62 )$$

Solvi għal x

$$x=0.98$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 0.7 b'x+0.62.

$$0.18x+0.9436=0.7x+0.434$$

Naqqas 0.7x miż-żewġ naħat.

$$0.18x+0.9436-0.7x=0.434$$

Ikkombina 0.18x u -0.7x biex tikseb -0.52x.

$$-0.52x+0.9436=0.434$$

Naqqas 0.9436 miż-żewġ naħat.

$$-0.52x=0.434-0.9436$$

Naqqas 0.9436 minn 0.434 biex tikseb -0.5096.

$$-0.52x=-0.5096$$

Iddividi ż-żewġ naħat b'-0.52.

$$x=\frac{-0.5096}{-0.52}$$

Espandi \frac{-0.5096}{-0.52} billi timmultiplika kemm in-numeratur kif ukoll id-denominatur b'10000.

$$x=\frac{-5096}{-5200}$$

Naqqas il-frazzjoni \frac{-5096}{-5200} għat-termini l-aktar baxxi billi testratta u tikkanċella barra -104.

$$x=\frac{49}{50}$$