Issolvi (x+6)^2=(x+14)(x+2)

$$( x + 6 ) ^ { 2 } = ( x + 14 ) ( x + 2 )$$

Solvi għal x

$$x=2$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(x+6\right)^{2}.

$$x^{2}+12x+36=\left(x+14\right)\left(x+2\right)$$

Uża l-propjetà distributtiva biex timmultiplika x+14 b'x+2 u kkombina termini simili.

$$x^{2}+12x+36=x^{2}+16x+28$$

Naqqas x^{2} miż-żewġ naħat.

$$x^{2}+12x+36-x^{2}=16x+28$$

Ikkombina x^{2} u -x^{2} biex tikseb 0.

$$12x+36=16x+28$$

Naqqas 16x miż-żewġ naħat.

$$12x+36-16x=28$$

Ikkombina 12x u -16x biex tikseb -4x.

$$-4x+36=28$$

Naqqas 36 miż-żewġ naħat.

$$-4x=28-36$$

Naqqas 36 minn 28 biex tikseb -8.

$$-4x=-8$$

Iddividi ż-żewġ naħat b'-4.

$$x=\frac{-8}{-4}$$

Iddividi -8 b'-4 biex tikseb2.

$$x=2$$