Issolvi (2.5p-1.5q)^2-(1.5p-2.5q)^2

$$( 2.5 p - 1.5 q ) ^ { 2 } - ( 1.5 p - 2.5 q ) ^ { 2 }$$

Evalwa

$$4\left(p^{2}-q^{2}\right)$$

Passi tas-Soluzzjonijiet

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(2.5p-1.5q\right)^{2}.

$$6.25p^{2}-7.5pq+2.25q^{2}-\left(1.5p-2.5q\right)^{2}$$

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(1.5p-2.5q\right)^{2}.

$$6.25p^{2}-7.5pq+2.25q^{2}-\left(2.25p^{2}-7.5pq+6.25q^{2}\right)$$

Biex issib l-oppost ta' 2.25p^{2}-7.5pq+6.25q^{2}, sib l-oppost ta' kull terminu.

$$6.25p^{2}-7.5pq+2.25q^{2}-2.25p^{2}+7.5pq-6.25q^{2}$$

Ikkombina 6.25p^{2} u -2.25p^{2} biex tikseb 4p^{2}.

$$4p^{2}-7.5pq+2.25q^{2}+7.5pq-6.25q^{2}$$

Ikkombina -7.5pq u 7.5pq biex tikseb 0.

$$4p^{2}+2.25q^{2}-6.25q^{2}$$

Ikkombina 2.25q^{2} u -6.25q^{2} biex tikseb -4q^{2}.

$$4p^{2}-4q^{2}$$

Espandi

$$4p^{2}-4q^{2}$$

Passi tas-Soluzzjonijiet

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(2.5p-1.5q\right)^{2}.

$$6.25p^{2}-7.5pq+2.25q^{2}-\left(1.5p-2.5q\right)^{2}$$

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(1.5p-2.5q\right)^{2}.

$$6.25p^{2}-7.5pq+2.25q^{2}-\left(2.25p^{2}-7.5pq+6.25q^{2}\right)$$

Biex issib l-oppost ta' 2.25p^{2}-7.5pq+6.25q^{2}, sib l-oppost ta' kull terminu.

$$6.25p^{2}-7.5pq+2.25q^{2}-2.25p^{2}+7.5pq-6.25q^{2}$$

Ikkombina 6.25p^{2} u -2.25p^{2} biex tikseb 4p^{2}.

$$4p^{2}-7.5pq+2.25q^{2}+7.5pq-6.25q^{2}$$

Ikkombina -7.5pq u 7.5pq biex tikseb 0.

$$4p^{2}+2.25q^{2}-6.25q^{2}$$

Ikkombina 2.25q^{2} u -6.25q^{2} biex tikseb -4q^{2}.

$$4p^{2}-4q^{2}$$