Issolvi (2x+1)^2-(2x-1)^2=16

$$( 2 x + 1 ) ^ { 2 } - ( 2 x - 1 ) ^ { 2 } = 16$$

Solvi għal x

$$x=2$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(2x+1\right)^{2}.

$$4x^{2}+4x+1-\left(2x-1\right)^{2}=16$$

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(2x-1\right)^{2}.

$$4x^{2}+4x+1-\left(4x^{2}-4x+1\right)=16$$

Biex issib l-oppost ta' 4x^{2}-4x+1, sib l-oppost ta' kull terminu.

$$4x^{2}+4x+1-4x^{2}+4x-1=16$$

Ikkombina 4x^{2} u -4x^{2} biex tikseb 0.

$$4x+1+4x-1=16$$

Ikkombina 4x u 4x biex tikseb 8x.

$$8x+1-1=16$$

Naqqas 1 minn 1 biex tikseb 0.

$$8x=16$$

Iddividi ż-żewġ naħat b'8.

$$x=\frac{16}{8}$$

Iddividi 16 b'8 biex tikseb2.

$$x=2$$