Issolvi (10*x+y)=5x(x+y)

$$( 10 * x + y ) = 5 x ( x + y )$$

Solvi għal y

$$y=-\frac{5x\left(2-x\right)}{1-5x}$$

$$x\neq \frac{1}{5}$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 5x b'x+y.

$$10x+y=5x^{2}+5xy$$

Naqqas 5xy miż-żewġ naħat.

$$10x+y-5xy=5x^{2}$$

Naqqas 10x miż-żewġ naħat.

$$y-5xy=5x^{2}-10x$$

Ikkombina t-termini kollha li fihom y.

$$\left(1-5x\right)y=5x^{2}-10x$$

Iddividi ż-żewġ naħat b'1-5x.

$$\frac{\left(1-5x\right)y}{1-5x}=\frac{5x\left(x-2\right)}{1-5x}$$

Meta tiddividi b'1-5x titneħħa l-multiplikazzjoni b'1-5x.

$$y=\frac{5x\left(x-2\right)}{1-5x}$$

Solvi għal x

$$x=-\frac{\sqrt{25y^{2}-80y+100}}{10}-\frac{y}{2}+1$$

$$x=\frac{\sqrt{25y^{2}-80y+100}}{10}-\frac{y}{2}+1$$