Issolvi {left(16+8x+2x^2/2+xright)}^2-4

$${ \left( \frac{ 16+8x+2 { x }^{ 2 } }{ 2+x } \right) }^{ 2 } -4$$

Evalwa

$$\frac{4\left(x^{2}+3x+6\right)\left(x^{2}+5x+10\right)}{\left(x+2\right)^{2}}$$

Passi Qosra tas-Soluzzjonijiet

Biex tgħolli \frac{16+8x+2x^{2}}{2+x} għal qawwa, għolli kemm in-numeratur u d-denominatur għall-qawwa u mbagħad iddividi.

$$\frac{\left(16+8x+2x^{2}\right)^{2}}{\left(2+x\right)^{2}}-4$$

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. Immultiplika 4 b'\frac{\left(2+x\right)^{2}}{\left(2+x\right)^{2}}.

$$\frac{\left(16+8x+2x^{2}\right)^{2}}{\left(2+x\right)^{2}}-\frac{4\left(2+x\right)^{2}}{\left(2+x\right)^{2}}$$

Billi \frac{\left(16+8x+2x^{2}\right)^{2}}{\left(2+x\right)^{2}} u \frac{4\left(2+x\right)^{2}}{\left(2+x\right)^{2}} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

$$\frac{\left(16+8x+2x^{2}\right)^{2}-4\left(2+x\right)^{2}}{\left(2+x\right)^{2}}$$

Agħmel il-multiplikazzjonijiet fi \left(16+8x+2x^{2}\right)^{2}-4\left(2+x\right)^{2}.

$$\frac{256+128x+32x^{2}+128x+64x^{2}+16x^{3}+32x^{2}+16x^{3}+4x^{4}-16-16x-4x^{2}}{\left(2+x\right)^{2}}$$

Ikkombina termini simili f'256+128x+32x^{2}+128x+64x^{2}+16x^{3}+32x^{2}+16x^{3}+4x^{4}-16-16x-4x^{2}.

$$\frac{240+240x+124x^{2}+32x^{3}+4x^{4}}{\left(2+x\right)^{2}}$$

Espandi \left(2+x\right)^{2}.

$$\frac{240+240x+124x^{2}+32x^{3}+4x^{4}}{x^{2}+4x+4}$$

Espandi

$$\frac{4\left(x^{4}+8x^{3}+31x^{2}+60x+60\right)}{\left(x+2\right)^{2}}$$

Passi Qosra tas-Soluzzjonijiet

Biex tgħolli \frac{16+8x+2x^{2}}{2+x} għal qawwa, għolli kemm in-numeratur u d-denominatur għall-qawwa u mbagħad iddividi.

$$\frac{\left(16+8x+2x^{2}\right)^{2}}{\left(2+x\right)^{2}}-4$$

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. Immultiplika 4 b'\frac{\left(2+x\right)^{2}}{\left(2+x\right)^{2}}.

$$\frac{\left(16+8x+2x^{2}\right)^{2}}{\left(2+x\right)^{2}}-\frac{4\left(2+x\right)^{2}}{\left(2+x\right)^{2}}$$

Billi \frac{\left(16+8x+2x^{2}\right)^{2}}{\left(2+x\right)^{2}} u \frac{4\left(2+x\right)^{2}}{\left(2+x\right)^{2}} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

$$\frac{\left(16+8x+2x^{2}\right)^{2}-4\left(2+x\right)^{2}}{\left(2+x\right)^{2}}$$

Agħmel il-multiplikazzjonijiet fi \left(16+8x+2x^{2}\right)^{2}-4\left(2+x\right)^{2}.

$$\frac{256+128x+32x^{2}+128x+64x^{2}+16x^{3}+32x^{2}+16x^{3}+4x^{4}-16-16x-4x^{2}}{\left(2+x\right)^{2}}$$

Ikkombina termini simili f'256+128x+32x^{2}+128x+64x^{2}+16x^{3}+32x^{2}+16x^{3}+4x^{4}-16-16x-4x^{2}.

$$\frac{240+240x+124x^{2}+32x^{3}+4x^{4}}{\left(2+x\right)^{2}}$$

Espandi \left(2+x\right)^{2}.

$$\frac{240+240x+124x^{2}+32x^{3}+4x^{4}}{x^{2}+4x+4}$$