Issolvi {l}{n=3^-2*9^(frac{3{2)}}+2^3}{o=35}{p=o}{q=p}{text{Solvefor}rtext{where}}{r=q}

$$\left. \begin{array} { l } { n = 3 ^ {-2} \cdot 9 ^ {{(\frac{3}{2})}} + 2 ^ {3} }\\ { o = 35 }\\ { p = o }\\ { q = p }\\ { \text{Solve for } r \text{ where} } \\ { r = q } \end{array} \right.$$

Solvi għal n, o, p, q, r

$$r=35$$

Passi tas-Soluzzjonijiet

Ikkunsidra l-ewwel ekwazzjoni. Ikkalkula 3 bil-power ta' -2 u tikseb \frac{1}{9}.

$$n=\frac{1}{9}\times 9^{\frac{3}{2}}+2^{3}$$

Ikkalkula 9 bil-power ta' \frac{3}{2} u tikseb 27.

$$n=\frac{1}{9}\times 27+2^{3}$$

Immultiplika \frac{1}{9} u 27 biex tikseb 3.

$$n=3+2^{3}$$

Ikkalkula 2 bil-power ta' 3 u tikseb 8.

$$n=3+8$$

Żid 3 u 8 biex tikseb 11.

$$n=11$$

Is-sistema issa solvuta.

$$n=11 o=35 p=35 q=35 r=35$$