Issolvi a/b+1-a/(b+1)^2

$$\frac { a } { b + 1 } - \frac { a } { ( b + 1 ) ^ { 2 } }$$

Evalwa

$$\frac{ab}{\left(b+1\right)^{2}}$$

Passi Qosra tas-Soluzzjonijiet

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. L-inqas multiplu komuni ta' b+1 u \left(b+1\right)^{2} huwa \left(b+1\right)^{2}. Immultiplika \frac{a}{b+1} b'\frac{b+1}{b+1}.

$$\frac{a\left(b+1\right)}{\left(b+1\right)^{2}}-\frac{a}{\left(b+1\right)^{2}}$$

Billi \frac{a\left(b+1\right)}{\left(b+1\right)^{2}} u \frac{a}{\left(b+1\right)^{2}} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

$$\frac{a\left(b+1\right)-a}{\left(b+1\right)^{2}}$$

Agħmel il-multiplikazzjonijiet fi a\left(b+1\right)-a.

$$\frac{ab+a-a}{\left(b+1\right)^{2}}$$

Ikkombina termini simili f'ab+a-a.

$$\frac{ab}{\left(b+1\right)^{2}}$$

Espandi \left(b+1\right)^{2}.

$$\frac{ab}{b^{2}+2b+1}$$

Espandi

$$\frac{ab}{\left(b+1\right)^{2}}$$

Passi Qosra tas-Soluzzjonijiet

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. L-inqas multiplu komuni ta' b+1 u \left(b+1\right)^{2} huwa \left(b+1\right)^{2}. Immultiplika \frac{a}{b+1} b'\frac{b+1}{b+1}.

$$\frac{a\left(b+1\right)}{\left(b+1\right)^{2}}-\frac{a}{\left(b+1\right)^{2}}$$

Billi \frac{a\left(b+1\right)}{\left(b+1\right)^{2}} u \frac{a}{\left(b+1\right)^{2}} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

$$\frac{a\left(b+1\right)-a}{\left(b+1\right)^{2}}$$

Agħmel il-multiplikazzjonijiet fi a\left(b+1\right)-a.

$$\frac{ab+a-a}{\left(b+1\right)^{2}}$$

Ikkombina termini simili f'ab+a-a.

$$\frac{ab}{\left(b+1\right)^{2}}$$

Espandi \left(b+1\right)^{2}.

$$\frac{ab}{b^{2}+2b+1}$$