Issolvi 1/2(x+2)+1/2(x-8)=7

$$\frac { 1 } { 2 } ( x + 2 ) + \frac { 1 } { 2 } ( x - 8 ) = 7$$

Solvi għal x

$$x=10$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika \frac{1}{2} b'x+2.

$$\frac{1}{2}x+\frac{1}{2}\times 2+\frac{1}{2}\left(x-8\right)=7$$

Annulla 2 u 2.

$$\frac{1}{2}x+1+\frac{1}{2}\left(x-8\right)=7$$

Uża l-propjetà distributtiva biex timmultiplika \frac{1}{2} b'x-8.

$$\frac{1}{2}x+1+\frac{1}{2}x+\frac{1}{2}\left(-8\right)=7$$

Immultiplika \frac{1}{2} u -8 biex tikseb \frac{-8}{2}.

$$\frac{1}{2}x+1+\frac{1}{2}x+\frac{-8}{2}=7$$

Iddividi -8 b'2 biex tikseb-4.

$$\frac{1}{2}x+1+\frac{1}{2}x-4=7$$

Ikkombina \frac{1}{2}x u \frac{1}{2}x biex tikseb x.

$$x+1-4=7$$

Naqqas 4 minn 1 biex tikseb -3.

$$x-3=7$$

Żid 3 maż-żewġ naħat.

$$x=7+3$$

Żid 7 u 3 biex tikseb 10.

$$x=10$$