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4%20-%203%20%60times%20(6%20%2B%202)%20%5E%202
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4
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2^{2}
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5 masalah yang serupa dengan:
4%20-%203%20%60times%20(6%20%2B%202)%20%5E%202
Masalah Sama dari Carian Web
\nJamie and Sara went shopping at the mall. Jamie spent 25 more than three times what Sara spent. Jamie spent 154.\nWhich equation will help us find how much Sara spent?\nx\/3 + 25 = 154\nx\/3 - 25 = ...
https://brainly.com/question/1889244
Jamie = 25 + 3(Sara)Jamie = 1543x + 25 = 154
What's the remainder when 2020\times 2018\times 2016\times 2014\times 2012\times 2010 is divided by (2015\times 2017)?
https://www.quora.com/Whats-the-remainder-when-2020-times-2018-times-2016-times-2014-times-2012-times-2010-is-divided-by-2015-times-2017
We write down the product 2020\times 2018\times 2016\times 2014\times 2012\times 2010 as (2017+3)(2015+3)(2015+1)(2015-1)(2015-3)(2015-5). We evaluate the above product, starting from the ...
Piotr Galkowski invested some money at 3.5% simple interest, and 5000 more than three times this amount at 4%. He earned 1440 in annual interest. How much did he invest at each rate?
https://brainly.com/question/2904916
so... Piotr invested two amounts, say \"a\" and \"b\", at 3.5% and 4% respectivelywhatever 3.5% of a is, and whatever 4% of b is, it ended up as 1440now, we know that \"b\" amount is \"5000 more than three times\" than \"a\" amountso \u00a0three times \"a\" is 3*a or 3a, now, 5000 more than that is 3a + 5000now, assuming this is for a year alone,how much is 3.5% of \"a\", well, 3\/100 * a, or 0.035ahow much is 4% of \"b\", well, 4\/100 * a, or 0.04bso.. whatever those amounts yielded are, they ended \u00a0up as 1440so \u00a0 \u00a0 \u00a0 ...
Difficulty proving the commutative law of multiplication on \mathbb{N}
https://math.stackexchange.com/questions/2375915/difficulty-proving-the-commutative-law-of-multiplication-on-mathbbn
It seems that what I wanted to prove in step 2. was not what I needed. What I need to prove in step 2. is n \times s(m) = (n \times m) + n. This I could prove without a problem, and therefore can ...
Books on the shelf problem
https://math.stackexchange.com/q/1030320
a is a stars and bars problem. Put the non-cooking books in a line. How many ways can you do that? From your answer to b, it appears you consider the five comic books to be distinct. Then you ...
Number of possibility of getting at least a pair of poker cards
https://math.stackexchange.com/q/1199311
The second formula overcounts the hands with at least one pair. For it multiple counts the the 2 pairs hands, the 3 of a kind hands, the 4 of a kind hands, and the full house hands. For ...
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4 - 3 \times 6 + 2
(4 - 3) \times 6 + 2
4 - 3 \times (6 + 2) ^ 2
\frac{4-3}{6}+2^2
5-4(7-9(5-1)) \times 3^3 -4
12-2(7-4)^2 \div 4
\frac{ \left( 4-3 \right) + { \left( 1+2 \right) }^{ 2 } }{ 6+ \left( 7-5 \right) }
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