Selesaikan 34*sin(x^2-5x)=2

$$34 \times \sin ( { x }^{ 2 } -5x ) =2$$

Selesaikan untuk x (complex solution)

$$x=\frac{5}{2}+\left(-\frac{1}{2}i\right)\left(-25+\left(-4\right)ArcTanI(\frac{1}{24}\times 2^{\frac{1}{2}})+\left(-8\right)\pi n_{1}\right)^{\frac{1}{2}}\text{, }n_{1}\in \mathrm{Z}$$

$$x=\frac{5}{2}+\frac{1}{2}i\left(-25+\left(-4\right)ArcTanI(\frac{1}{24}\times 2^{\frac{1}{2}})+\left(-8\right)\pi n_{1}\right)^{\frac{1}{2}}\text{, }n_{1}\in \mathrm{Z}$$

$$x=\frac{5}{2}+\left(-\frac{1}{2}i\right)\left(-25+\left(-8\right)\pi n_{5}+4i\ln(\frac{1}{17}i+\left(-\frac{12}{17}\right)\times 2^{\frac{1}{2}})\right)^{\frac{1}{2}}\text{, }n_{5}\in \mathrm{Z}$$

$$x=\frac{5}{2}+\frac{1}{2}i\left(-25+\left(-8\right)\pi n_{5}+4i\ln(\frac{1}{17}i+\left(-\frac{12}{17}\right)\times 2^{\frac{1}{2}})\right)^{\frac{1}{2}}\text{, }n_{5}\in \mathrm{Z}$$

Selesaikan untuk x

$$x=\frac{-\sqrt{8\pi n_{2}+4\pi +25-4\arcsin(\frac{1}{17})}+5}{2}\text{, }n_{2}\in \mathrm{Z}\text{, }n_{2}\geq -1$$

$$x=\frac{\sqrt{8\pi n_{2}+4\pi +25-4\arcsin(\frac{1}{17})}+5}{2}\text{, }n_{2}\in \mathrm{Z}\text{, }n_{2}\geq -1$$

$$x=\frac{-\sqrt{8\pi n_{1}+4\arcsin(\frac{1}{17})+25}+5}{2}\text{, }n_{1}\in \mathrm{Z}\text{, }n_{1}\geq -1$$

$$x=\frac{\sqrt{8\pi n_{1}+4\arcsin(\frac{1}{17})+25}+5}{2}\text{, }n_{1}\in \mathrm{Z}\text{, }n_{1}\geq -1$$