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\frac{\mathrm{d}}{\mathrm{d}\xi }(\sin(\xi ))=\left(\lim_{h\to 0}\frac{\sin(\xi +h)-\sin(\xi )}{h}\right)
Bagi fungsi f\left(x\right), terbitannya adalah had bagi \frac{f\left(x+h\right)-f\left(x\right)}{h} apabila h pergi ke 0, jika had tersebut wujud.
\lim_{h\to 0}\frac{\sin(h+\xi )-\sin(\xi )}{h}
Gunakan Formula Hasil Tambah untuk Sinus.
\lim_{h\to 0}\frac{\sin(\xi )\left(\cos(h)-1\right)+\cos(\xi )\sin(h)}{h}
Faktorkan \sin(\xi ).
\left(\lim_{h\to 0}\sin(\xi )\right)\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)+\left(\lim_{h\to 0}\cos(\xi )\right)\left(\lim_{h\to 0}\frac{\sin(h)}{h}\right)
Tulis semula had.
\sin(\xi )\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)+\cos(\xi )\left(\lim_{h\to 0}\frac{\sin(h)}{h}\right)
Gunakan fakta bahawa \xi ialah pemalar apabila mengira had semasa h pergi ke 0.
\sin(\xi )\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)+\cos(\xi )
Had \lim_{\xi \to 0}\frac{\sin(\xi )}{\xi } ialah 1.
\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)=\left(\lim_{h\to 0}\frac{\left(\cos(h)-1\right)\left(\cos(h)+1\right)}{h\left(\cos(h)+1\right)}\right)
Untuk menilaikan had \lim_{h\to 0}\frac{\cos(h)-1}{h}, mula-mula darabkan pengangka dan penyebut dengan \cos(h)+1.
\lim_{h\to 0}\frac{\left(\cos(h)\right)^{2}-1}{h\left(\cos(h)+1\right)}
Darabkan \cos(h)+1 kali \cos(h)-1.
\lim_{h\to 0}-\frac{\left(\sin(h)\right)^{2}}{h\left(\cos(h)+1\right)}
Gunakan Identiti Phythagoras.
\left(\lim_{h\to 0}-\frac{\sin(h)}{h}\right)\left(\lim_{h\to 0}\frac{\sin(h)}{\cos(h)+1}\right)
Tulis semula had.
-\left(\lim_{h\to 0}\frac{\sin(h)}{\cos(h)+1}\right)
Had \lim_{\xi \to 0}\frac{\sin(\xi )}{\xi } ialah 1.
\left(\lim_{h\to 0}\frac{\sin(h)}{\cos(h)+1}\right)=0
Gunakan fakta bahawa \frac{\sin(h)}{\cos(h)+1} adalah selanjar pada 0.
\cos(\xi )
Gantikan nilai 0 ke dalam ungkapan \sin(\xi )\left(\lim_{h\to 0}\frac{\cos(h)-1}{h}\right)+\cos(\xi ).