Selesaikan untuk X, A, B, t (complex solution)
t\in \mathrm{C}
X=\frac{B^{t}+3B}{5}
A=\frac{2B-B^{t}}{5}
B\in \mathrm{C}
Selesaikan untuk X, A, B, t
\left\{\begin{matrix}\\t>0\text{, }X=\frac{B^{t}+3B}{5}\text{, }A=\frac{2B-B^{t}}{5}\text{, }B=0\text{; }t\in \mathrm{R}\text{, }X=\frac{B^{t}+3B}{5}\text{, }A=\frac{2B-B^{t}}{5}\text{, }B>0\text{, }&\text{unconditionally}\\t\in \mathrm{R}\text{, }X=\frac{B^{t}+3B}{5}\text{, }A=\frac{2B-B^{t}}{5}\text{, }B<0\text{, }&Denominator(t)\text{bmod}2=1\end{matrix}\right.
Kongsi
Disalin ke papan klip
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