y=mx+a/m सोडवा

$$y = m x + \frac { a } { m }$$

m साठी सोडवा (जटिल उत्तर)

$$\left\{\begin{matrix}m=\frac{\sqrt{y^{2}-4ax}+y}{2x}\text{, }&\left(a\neq 0\text{ and }x\neq 0\right)\text{ or }\left(arg(y)<\pi \text{ and }y\neq 0\text{ and }x\neq 0\right)\\m=-\frac{\sqrt{y^{2}-4ax}-y}{2x}\text{, }&\left(a\neq 0\text{ and }x\neq 0\right)\text{ or }\left(|\frac{arg(y^{2})}{2}-arg(y)|\geq \pi \text{ and }y\neq 0\text{ and }x\neq 0\right)\\m=\frac{a}{y}\text{, }&a\neq 0\text{ and }y\neq 0\text{ and }x=0\\m\neq 0\text{, }&x=0\text{ and }y=0\text{ and }a=0\end{matrix}\right.$$

a साठी सोडवा

$$a=-m\left(mx-y\right)$$

$$m\neq 0$$