+tanθ=p सोडवा

$$+ \tan \theta = p$$

p साठी सोडवा

$$p=\tan(\theta )$$

$$\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =\pi n_{1}+\frac{\pi }{2}$$

θ साठी सोडवा

$$\theta =\pi +2n_{3}\pi +arcSin(p\left(p^{2}+1\right)^{-\frac{1}{2}})\text{, }n_{3}\in \mathrm{Z}\text{, }\exists n_{42}\in \mathrm{Z}\text{ : }\left(n_{3}>\left(-\frac{1}{2}\right)\left(arcSin(p\left(p^{2}+1\right)^{-\frac{1}{2}})+\frac{1}{2}\pi +\left(-1\right)\pi n_{42}\right)\pi ^{-1}\text{ and }n_{3}<\left(-\frac{1}{2}\right)\left(arcSin(p\left(p^{2}+1\right)^{-\frac{1}{2}})+\left(-\frac{1}{2}\right)\pi +\left(-1\right)\pi n_{42}\right)\pi ^{-1}\right)\text{ and }\nexists n_{1}\in \mathrm{Z}\text{ : }\pi +2n_{3}\pi +arcSin(p\left(p^{2}+1\right)^{-\frac{1}{2}})=\frac{1}{2}\pi +\pi n_{1}$$

$$\theta =arcSin(p\left(p^{2}+1\right)^{-\frac{1}{2}})+2\pi n_{22}\text{, }n_{22}\in \mathrm{Z}\text{, }\nexists n_{1}\in \mathrm{Z}\text{ : }arcSin(p\left(p^{2}+1\right)^{-\frac{1}{2}})+2\pi n_{22}=\frac{1}{2}\pi +\pi n_{1}$$