Решете y=3*tanθ

$$y = 3 \cdot \tan \theta$$

Реши за y

$$y=3\tan(\theta )$$

$$\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =\pi n_{1}+\frac{\pi }{2}$$

Реши за θ

$$\theta =\pi +2n_{3}\pi +arcSin(y\left(y^{2}+9\right)^{-\frac{1}{2}})\text{, }n_{3}\in \mathrm{Z}\text{, }\exists n_{42}\in \mathrm{Z}\text{ : }\left(n_{3}>\left(-\frac{1}{2}\right)\left(\frac{1}{2}\pi +\left(-1\right)\pi n_{42}+arcSin(y\left(y^{2}+9\right)^{-\frac{1}{2}})\right)\pi ^{-1}\text{ and }n_{3}<\left(-\frac{1}{2}\right)\left(\left(-\frac{1}{2}\right)\pi +\left(-1\right)\pi n_{42}+arcSin(y\left(y^{2}+9\right)^{-\frac{1}{2}})\right)\pi ^{-1}\right)$$

$$\theta =arcSin(y\left(y^{2}+9\right)^{-\frac{1}{2}})+2\pi n_{22}\text{, }n_{22}\in \mathrm{Z}\text{, }\exists n_{42}\in \mathrm{Z}\text{ : }\left(n_{42}<\left(arcSin(y\left(y^{2}+9\right)^{-\frac{1}{2}})+2\pi n_{22}+\left(-\frac{1}{2}\right)\pi \right)\pi ^{-1}\text{ and }n_{42}>\left(arcSin(y\left(y^{2}+9\right)^{-\frac{1}{2}})+2\pi n_{22}+\left(-\frac{3}{2}\right)\pi \right)\pi ^{-1}\right)$$