Whakaoti i te zz=2+50

$$z z = 2 + 50$$

Whakaoti mō z

$$z=2\sqrt{13}\approx 7.211102551$$

$$z=-2\sqrt{13}\approx -7.211102551$$

Ngā Upane mā te Kimi Pūtakerua

Whakareatia te z ki te z, ka z^{2}.

$$z^{2}=2+50$$

Tāpirihia te 2 ki te 50, ka 52.

$$z^{2}=52$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$z=2\sqrt{13} z=-2\sqrt{13}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te z ki te z, ka z^{2}.

$$z^{2}=2+50$$

Tāpirihia te 2 ki te 50, ka 52.

$$z^{2}=52$$

Tangohia te 52 mai i ngā taha e rua.

$$z^{2}-52=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -52 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$z=\frac{0±\sqrt{0^{2}-4\left(-52\right)}}{2}$$

Pūrua 0.

$$z=\frac{0±\sqrt{-4\left(-52\right)}}{2}$$

Whakareatia -4 ki te -52.

$$z=\frac{0±\sqrt{208}}{2}$$

Tuhia te pūtakerua o te 208.

$$z=\frac{0±4\sqrt{13}}{2}$$

Nā, me whakaoti te whārite z=\frac{0±4\sqrt{13}}{2} ina he tāpiri te ±.

$$z=2\sqrt{13}$$

Nā, me whakaoti te whārite z=\frac{0±4\sqrt{13}}{2} ina he tango te ±.

$$z=-2\sqrt{13}$$

Kua oti te whārite te whakatau.

$$z=2\sqrt{13} z=-2\sqrt{13}$$