Whakaoti i te z_{1}*z_{2}=(1-i)(sqrt{3}+i)

$$z _ { 1 } \cdot z _ { 2 } = ( 1 - i ) ( \sqrt { 3 } + i )$$

Whakaoti mō z_1

$$z_{1}=-\frac{\sqrt{3}\left(-1+i\right)+\left(-1-i\right)}{z_{2}}$$

$$z_{2}\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 1-i ki te \sqrt{3}+i.

$$z_{1}z_{2}=\left(1-i\right)\sqrt{3}+\left(1+i\right)$$

He hanga arowhānui tō te whārite.

$$z_{2}z_{1}=\sqrt{3}\left(1-i\right)+\left(1+i\right)$$

Whakawehea ngā taha e rua ki te z_{2}.

$$\frac{z_{2}z_{1}}{z_{2}}=\frac{\sqrt{3}\left(1-i\right)+\left(1+i\right)}{z_{2}}$$

Mā te whakawehe ki te z_{2} ka wetekia te whakareanga ki te z_{2}.

$$z_{1}=\frac{\sqrt{3}\left(1-i\right)+\left(1+i\right)}{z_{2}}$$

Whakaoti mō z_2

$$z_{2}=-\frac{\sqrt{3}\left(-1+i\right)+\left(-1-i\right)}{z_{1}}$$

$$z_{1}\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 1-i ki te \sqrt{3}+i.

$$z_{1}z_{2}=\left(1-i\right)\sqrt{3}+\left(1+i\right)$$

He hanga arowhānui tō te whārite.

$$z_{1}z_{2}=\sqrt{3}\left(1-i\right)+\left(1+i\right)$$

Whakawehea ngā taha e rua ki te z_{1}.

$$\frac{z_{1}z_{2}}{z_{1}}=\frac{\sqrt{3}\left(1-i\right)+\left(1+i\right)}{z_{1}}$$

Mā te whakawehe ki te z_{1} ka wetekia te whakareanga ki te z_{1}.

$$z_{2}=\frac{\sqrt{3}\left(1-i\right)+\left(1+i\right)}{z_{1}}$$