Whakaoti i te z^2+8=9z

$$z ^ { 2 } + 8 = 9 z$$

Whakaoti mō z

$$z=1$$

$$z=8$$

Ngā Upane Whakamahi Tauwehe

Tangohia te 9z mai i ngā taha e rua.

$$z^{2}+8-9z=0$$

Hurinahatia te pūrau ki te āhua tānga ngahuru. Whakaraupapahia ngā kīanga tau mai i te pū teitei rawa ki te mea iti rawa.

$$z^{2}-9z+8=0$$

Hei whakaoti i te whārite, whakatauwehea te z^{2}-9z+8 mā te whakamahi i te tātai z^{2}+\left(a+b\right)z+ab=\left(z+a\right)\left(z+b\right). Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=-9 ab=8$$

I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōraro te a+b, he tōraro hoki a a me b. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua 8.

$$-1,-8 -2,-4$$

Tātaihia te tapeke mō ia takirua.

$$-1-8=-9 -2-4=-6$$

Ko te otinga te takirua ka hoatu i te tapeke -9.

$$a=-8 b=-1$$

Me tuhi anō te kīanga whakatauwehe \left(z+a\right)\left(z+b\right) mā ngā uara i tātaihia.

$$\left(z-8\right)\left(z-1\right)$$

Hei kimi otinga whārite, me whakaoti te z-8=0 me te z-1=0.

$$z=8 z=1$$

Ngā Upane Whakamahi Tauwehe Mā te Whakarōpū

Tangohia te 9z mai i ngā taha e rua.

$$z^{2}+8-9z=0$$

Hurinahatia te pūrau ki te āhua tānga ngahuru. Whakaraupapahia ngā kīanga tau mai i te pū teitei rawa ki te mea iti rawa.

$$z^{2}-9z+8=0$$

Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei z^{2}+az+bz+8. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=-9 ab=1\times 8=8$$

I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōraro te a+b, he tōraro hoki a a me b. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua 8.

$$-1,-8 -2,-4$$

Tātaihia te tapeke mō ia takirua.

$$-1-8=-9 -2-4=-6$$

Ko te otinga te takirua ka hoatu i te tapeke -9.

$$a=-8 b=-1$$

Tuhia anō te z^{2}-9z+8 hei \left(z^{2}-8z\right)+\left(-z+8\right).

$$\left(z^{2}-8z\right)+\left(-z+8\right)$$

Tauwehea te z i te tuatahi me te -1 i te rōpū tuarua.

$$z\left(z-8\right)-\left(z-8\right)$$

Whakatauwehea atu te kīanga pātahi z-8 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(z-8\right)\left(z-1\right)$$

Hei kimi otinga whārite, me whakaoti te z-8=0 me te z-1=0.

$$z=8 z=1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 9z mai i ngā taha e rua.

$$z^{2}+8-9z=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$z^{2}-9z+8=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, -9 mō b, me 8 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$z=\frac{-\left(-9\right)±\sqrt{\left(-9\right)^{2}-4\times 8}}{2}$$

Pūrua -9.

$$z=\frac{-\left(-9\right)±\sqrt{81-4\times 8}}{2}$$

Whakareatia -4 ki te 8.

$$z=\frac{-\left(-9\right)±\sqrt{81-32}}{2}$$

Tāpiri 81 ki te -32.

$$z=\frac{-\left(-9\right)±\sqrt{49}}{2}$$

Tuhia te pūtakerua o te 49.

$$z=\frac{-\left(-9\right)±7}{2}$$

Ko te tauaro o -9 ko 9.

$$z=\frac{9±7}{2}$$

Nā, me whakaoti te whārite z=\frac{9±7}{2} ina he tāpiri te ±. Tāpiri 9 ki te 7.

$$z=\frac{16}{2}$$

Whakawehe 16 ki te 2.

$$z=8$$

Nā, me whakaoti te whārite z=\frac{9±7}{2} ina he tango te ±. Tango 7 mai i 9.

$$z=\frac{2}{2}$$

Whakawehe 2 ki te 2.

$$z=1$$

Kua oti te whārite te whakatau.

$$z=8 z=1$$

Ngā Upane mō te Whakaoti i te Pūrua

Tangohia te 9z mai i ngā taha e rua.

$$z^{2}+8-9z=0$$

Tangohia te 8 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$z^{2}-9z=-8$$

Whakawehea te -9, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -\frac{9}{2}. Nā, tāpiria te pūrua o te -\frac{9}{2} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$z^{2}-9z+\left(-\frac{9}{2}\right)^{2}=-8+\left(-\frac{9}{2}\right)^{2}$$

Pūruatia -\frac{9}{2} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$z^{2}-9z+\frac{81}{4}=-8+\frac{81}{4}$$

Tāpiri -8 ki te \frac{81}{4}.

$$z^{2}-9z+\frac{81}{4}=\frac{49}{4}$$

Tauwehea z^{2}-9z+\frac{81}{4}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(z-\frac{9}{2}\right)^{2}=\frac{49}{4}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(z-\frac{9}{2}\right)^{2}}=\sqrt{\frac{49}{4}}$$

Whakarūnātia.

$$z-\frac{9}{2}=\frac{7}{2} z-\frac{9}{2}=-\frac{7}{2}$$

Me tāpiri \frac{9}{2} ki ngā taha e rua o te whārite.

$$z=8 z=1$$