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\frac{\mathrm{d}}{\mathrm{d}z}(z^{2}+10z+48)
Whakareatia te 24 ki te 2, ka 48.
2z^{2-1}+10z^{1-1}
Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.
2z^{1}+10z^{1-1}
Tango 1 mai i 2.
2z^{1}+10z^{0}
Tango 1 mai i 1.
2z+10z^{0}
Mō tētahi kupu t, t^{1}=t.
2z+10\times 1
Mō tētahi kupu t mahue te 0, t^{0}=1.
2z+10
Mō tētahi kupu t, t\times 1=t me 1t=t.
z^{2}+10z+48
Whakareatia te 24 ki te 2, ka 48.