Whakaoti i te z=a-b/b+c

$$z = \frac { a - b } { b } + c$$

Whakaoti mō b

$$\left\{\begin{matrix}b=-\frac{a}{-z+c-1}\text{, }&a\neq 0\text{ and }z\neq c-1\\b\neq 0\text{, }&a=0\text{ and }z=c-1\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe b ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te b.

$$zb=a-b+bc$$

Me tāpiri te b ki ngā taha e rua.

$$zb+b=a+bc$$

Tangohia te bc mai i ngā taha e rua.

$$zb+b-bc=a$$

Pahekotia ngā kīanga tau katoa e whai ana i te b.

$$\left(z+1-c\right)b=a$$

He hanga arowhānui tō te whārite.

$$\left(z-c+1\right)b=a$$

Whakawehea ngā taha e rua ki te z+1-c.

$$\frac{\left(z-c+1\right)b}{z-c+1}=\frac{a}{z-c+1}$$

Mā te whakawehe ki te z+1-c ka wetekia te whakareanga ki te z+1-c.

$$b=\frac{a}{z-c+1}$$

Tē taea kia ōrite te tāupe b ki 0.

$$b=\frac{a}{z-c+1}\text{, }b\neq 0$$

Whakaoti mō a

$$a=b\left(z-c+1\right)$$

$$b\neq 0$$