Whakaoti i te y-1=x+2/x+1

$$y-1 = \frac{ x+2 }{ x+1 }$$

Whakaoti mō x

$$x=-\frac{y-3}{y-2}$$

$$y\neq 2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki -1 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x+1.

$$\left(x+1\right)y+\left(x+1\right)\left(-1\right)=x+2$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+1 ki te y.

$$xy+y+\left(x+1\right)\left(-1\right)=x+2$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+1 ki te -1.

$$xy+y-x-1=x+2$$

Tangohia te x mai i ngā taha e rua.

$$xy+y-x-1-x=2$$

Pahekotia te -x me -x, ka -2x.

$$xy+y-2x-1=2$$

Tangohia te y mai i ngā taha e rua.

$$xy-2x-1=2-y$$

Me tāpiri te 1 ki ngā taha e rua.

$$xy-2x=2-y+1$$

Tāpirihia te 2 ki te 1, ka 3.

$$xy-2x=3-y$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(y-2\right)x=3-y$$

Whakawehea ngā taha e rua ki te y-2.

$$\frac{\left(y-2\right)x}{y-2}=\frac{3-y}{y-2}$$

Mā te whakawehe ki te y-2 ka wetekia te whakareanga ki te y-2.

$$x=\frac{3-y}{y-2}$$

Tē taea kia ōrite te tāupe x ki -1.

$$x=\frac{3-y}{y-2}\text{, }x\neq -1$$

Whakaoti mō y

$$y=\frac{2x+3}{x+1}$$

$$x\neq -1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te x+1.

$$\left(x+1\right)y+\left(x+1\right)\left(-1\right)=x+2$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+1 ki te y.

$$xy+y+\left(x+1\right)\left(-1\right)=x+2$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+1 ki te -1.

$$xy+y-x-1=x+2$$

Me tāpiri te x ki ngā taha e rua.

$$xy+y-1=x+2+x$$

Pahekotia te x me x, ka 2x.

$$xy+y-1=2x+2$$

Me tāpiri te 1 ki ngā taha e rua.

$$xy+y=2x+2+1$$

Tāpirihia te 2 ki te 1, ka 3.

$$xy+y=2x+3$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(x+1\right)y=2x+3$$

Whakawehea ngā taha e rua ki te x+1.

$$\frac{\left(x+1\right)y}{x+1}=\frac{2x+3}{x+1}$$

Mā te whakawehe ki te x+1 ka wetekia te whakareanga ki te x+1.

$$y=\frac{2x+3}{x+1}$$