Whakaoti i te y=5sqrt{3x+1}

$$y=5 \sqrt{ 3x+1 }$$

Whakaoti mō x

$$x=\frac{y^{2}-25}{75}$$

$$y\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$5\sqrt{3x+1}=y$$

Whakawehea ngā taha e rua ki te 5.

$$\frac{5\sqrt{3x+1}}{5}=\frac{y}{5}$$

Mā te whakawehe ki te 5 ka wetekia te whakareanga ki te 5.

$$\sqrt{3x+1}=\frac{y}{5}$$

Pūruatia ngā taha e rua o te whārite.

$$3x+1=\frac{y^{2}}{25}$$

Me tango 1 mai i ngā taha e rua o te whārite.

$$3x+1-1=\frac{y^{2}}{25}-1$$

Mā te tango i te 1 i a ia ake anō ka toe ko te 0.

$$3x=\frac{y^{2}}{25}-1$$

Whakawehea ngā taha e rua ki te 3.

$$\frac{3x}{3}=\frac{\frac{y^{2}}{25}-1}{3}$$

Mā te whakawehe ki te 3 ka wetekia te whakareanga ki te 3.

$$x=\frac{\frac{y^{2}}{25}-1}{3}$$

Whakawehe -1+\frac{y^{2}}{25} ki te 3.

$$x=\frac{y^{2}}{75}-\frac{1}{3}$$

Whakaoti mō x (complex solution)

$$x=\frac{y^{2}-25}{75}$$

$$arg(y)<\pi \text{ or }y=0$$

Whakaoti mō y

$$y=5\sqrt{3x+1}$$

$$x\geq -\frac{1}{3}$$