Whakaoti mō x
x=\frac{y^{2}+2}{5}
y\geq 0
Whakaoti mō x (complex solution)
x=\frac{y^{2}+2}{5}
arg(y)<\pi \text{ or }y=0
Whakaoti mō y
y=\sqrt{5x-2}
x\geq \frac{2}{5}
Graph
Tohaina
Kua tāruatia ki te papatopenga
\sqrt{5x-2}=y
Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.
5x-2=y^{2}
Pūruatia ngā taha e rua o te whārite.
5x-2-\left(-2\right)=y^{2}-\left(-2\right)
Me tāpiri 2 ki ngā taha e rua o te whārite.
5x=y^{2}-\left(-2\right)
Mā te tango i te -2 i a ia ake anō ka toe ko te 0.
5x=y^{2}+2
Tango -2 mai i y^{2}.
\frac{5x}{5}=\frac{y^{2}+2}{5}
Whakawehea ngā taha e rua ki te 5.
x=\frac{y^{2}+2}{5}
Mā te whakawehe ki te 5 ka wetekia te whakareanga ki te 5.
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