Whakaoti i te y=sqrt{5-x}

$$y= \sqrt{ 5-x }$$

Whakaoti mō x

$$x=5-y^{2}$$

$$y\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\sqrt{5-x}=y$$

Pūruatia ngā taha e rua o te whārite.

$$-x+5=y^{2}$$

Me tango 5 mai i ngā taha e rua o te whārite.

$$-x+5-5=y^{2}-5$$

Mā te tango i te 5 i a ia ake anō ka toe ko te 0.

$$-x=y^{2}-5$$

Whakawehea ngā taha e rua ki te -1.

$$\frac{-x}{-1}=\frac{y^{2}-5}{-1}$$

Mā te whakawehe ki te -1 ka wetekia te whakareanga ki te -1.

$$x=\frac{y^{2}-5}{-1}$$

Whakawehe y^{2}-5 ki te -1.

$$x=5-y^{2}$$

Whakaoti mō x (complex solution)

$$x=5-y^{2}$$

$$arg(y)<\pi \text{ or }y=0$$

Whakaoti mō y

$$y=\sqrt{5-x}$$

$$x\leq 5$$