Whakaoti i te y=sqrt{4-7x}

$$y= \sqrt{ 4-7x }$$

Whakaoti mō x

$$x=\frac{4-y^{2}}{7}$$

$$y\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\sqrt{4-7x}=y$$

Pūruatia ngā taha e rua o te whārite.

$$-7x+4=y^{2}$$

Me tango 4 mai i ngā taha e rua o te whārite.

$$-7x+4-4=y^{2}-4$$

Mā te tango i te 4 i a ia ake anō ka toe ko te 0.

$$-7x=y^{2}-4$$

Whakawehea ngā taha e rua ki te -7.

$$\frac{-7x}{-7}=\frac{y^{2}-4}{-7}$$

Mā te whakawehe ki te -7 ka wetekia te whakareanga ki te -7.

$$x=\frac{y^{2}-4}{-7}$$

Whakawehe y^{2}-4 ki te -7.

$$x=\frac{4-y^{2}}{7}$$

Whakaoti mō x (complex solution)

$$x=\frac{4-y^{2}}{7}$$

$$arg(y)<\pi \text{ or }y=0$$

Whakaoti mō y

$$y=\sqrt{4-7x}$$

$$x\leq \frac{4}{7}$$