Whakaoti i te y=8x-3/x+1

$$y= \frac{ 8x-3 }{ x+1 }$$

Whakaoti mō x

$$x=-\frac{y+3}{y-8}$$

$$y\neq 8$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki -1 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x+1.

$$y\left(x+1\right)=8x-3$$

Whakamahia te āhuatanga tohatoha hei whakarea te y ki te x+1.

$$yx+y=8x-3$$

Tangohia te 8x mai i ngā taha e rua.

$$yx+y-8x=-3$$

Tangohia te y mai i ngā taha e rua.

$$yx-8x=-3-y$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(y-8\right)x=-3-y$$

He hanga arowhānui tō te whārite.

$$\left(y-8\right)x=-y-3$$

Whakawehea ngā taha e rua ki te y-8.

$$\frac{\left(y-8\right)x}{y-8}=\frac{-y-3}{y-8}$$

Mā te whakawehe ki te y-8 ka wetekia te whakareanga ki te y-8.

$$x=\frac{-y-3}{y-8}$$

Whakawehe -3-y ki te y-8.

$$x=-\frac{y+3}{y-8}$$

Tē taea kia ōrite te tāupe x ki -1.

$$x=-\frac{y+3}{y-8}\text{, }x\neq -1$$

Whakaoti mō y

$$y=-\frac{3-8x}{x+1}$$

$$x\neq -1$$