Whakaoti i te y=1-x/x-3

$$y= \frac{ 1-x }{ x-3 }$$

Whakaoti mō x

$$x=\frac{3y+1}{y+1}$$

$$y\neq -1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki 3 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x-3.

$$y\left(x-3\right)=1-x$$

Whakamahia te āhuatanga tohatoha hei whakarea te y ki te x-3.

$$yx-3y=1-x$$

Me tāpiri te x ki ngā taha e rua.

$$yx-3y+x=1$$

Me tāpiri te 3y ki ngā taha e rua.

$$yx+x=1+3y$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(y+1\right)x=1+3y$$

He hanga arowhānui tō te whārite.

$$\left(y+1\right)x=3y+1$$

Whakawehea ngā taha e rua ki te y+1.

$$\frac{\left(y+1\right)x}{y+1}=\frac{3y+1}{y+1}$$

Mā te whakawehe ki te y+1 ka wetekia te whakareanga ki te y+1.

$$x=\frac{3y+1}{y+1}$$

Tē taea kia ōrite te tāupe x ki 3.

$$x=\frac{3y+1}{y+1}\text{, }x\neq 3$$

Whakaoti mō y

$$y=-\frac{x-1}{x-3}$$

$$x\neq 3$$