Whakaoti i te y_{1}(t)=8tquady_{2}(t)=-8t+54

$$y _ { 1 } ( t ) = 8 t \quad y _ { 2 } ( t ) = - 8 t + 54$$

Whakaoti mō y_2

$$y_{2}=\frac{27-4t}{4t^{2}}$$

$$t\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te t ki te t, ka t^{2}.

$$8t^{2}y_{2}=-8t+54$$

He hanga arowhānui tō te whārite.

$$8t^{2}y_{2}=54-8t$$

Whakawehea ngā taha e rua ki te 8t^{2}.

$$\frac{8t^{2}y_{2}}{8t^{2}}=\frac{54-8t}{8t^{2}}$$

Mā te whakawehe ki te 8t^{2} ka wetekia te whakareanga ki te 8t^{2}.

$$y_{2}=\frac{54-8t}{8t^{2}}$$

Whakawehe -8t+54 ki te 8t^{2}.

$$y_{2}=\frac{\frac{27}{4}-t}{t^{2}}$$

Whakaoti mō t

$$\left\{\begin{matrix}t=\frac{\sqrt{27y_{2}+1}-1}{2y_{2}}\text{; }t=-\frac{\sqrt{27y_{2}+1}+1}{2y_{2}}\text{, }&y_{2}\neq 0\text{ and }y_{2}\geq -\frac{1}{27}\\t=\frac{27}{4}=6.75\text{, }&y_{2}=0\end{matrix}\right.$$