Whakaoti i te y_{0}=4*(1/8)^2-1/8-3

$$y _ { 0 } = 4 \cdot ( \frac { 1 } { 8 } ) ^ { 2 } - \frac { 1 } { 8 } - 3$$

Whakaoti mō y_0

$$y_{0} = -\frac{49}{16} = -3\frac{1}{16} = -3.0625$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te \frac{1}{8} mā te pū o 2, kia riro ko \frac{1}{64}.

$$y_{0}=4\times \frac{1}{64}-\frac{1}{8}-3$$

Whakareatia te 4 ki te \frac{1}{64}, ka \frac{4}{64}.

$$y_{0}=\frac{4}{64}-\frac{1}{8}-3$$

Whakahekea te hautanga \frac{4}{64} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 4.

$$y_{0}=\frac{1}{16}-\frac{1}{8}-3$$

Ko te maha noa iti rawa atu o 16 me 8 ko 16. Me tahuri \frac{1}{16} me \frac{1}{8} ki te hautau me te tautūnga 16.

$$y_{0}=\frac{1}{16}-\frac{2}{16}-3$$

Tā te mea he rite te tauraro o \frac{1}{16} me \frac{2}{16}, me tango rāua mā te tango i ō raua taurunga.

$$y_{0}=\frac{1-2}{16}-3$$

Tangohia te 2 i te 1, ka -1.

$$y_{0}=-\frac{1}{16}-3$$

Me tahuri te 3 ki te hautau \frac{48}{16}.

$$y_{0}=-\frac{1}{16}-\frac{48}{16}$$

Tā te mea he rite te tauraro o -\frac{1}{16} me \frac{48}{16}, me tango rāua mā te tango i ō raua taurunga.

$$y_{0}=\frac{-1-48}{16}$$

Tangohia te 48 i te -1, ka -49.

$$y_{0}=-\frac{49}{16}$$

Tautapa y_0

$$y_{0}≔-\frac{49}{16}$$