Whakaoti i te y-3=-1/2f(2x-4)

$$y - 3 = - \frac { 1 } { 2 } f ( 2 x - 4 )$$

Whakaoti mō f

$$\left\{\begin{matrix}f=-\frac{y-3}{x-2}\text{, }&x\neq 2\\f\in \mathrm{R}\text{, }&y=3\text{ and }x=2\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{1}{2}f ki te 2x-4.

$$y-3=-fx+2f$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-fx+2f=y-3$$

Pahekotia ngā kīanga tau katoa e whai ana i te f.

$$\left(-x+2\right)f=y-3$$

He hanga arowhānui tō te whārite.

$$\left(2-x\right)f=y-3$$

Whakawehea ngā taha e rua ki te 2-x.

$$\frac{\left(2-x\right)f}{2-x}=\frac{y-3}{2-x}$$

Mā te whakawehe ki te 2-x ka wetekia te whakareanga ki te 2-x.

$$f=\frac{y-3}{2-x}$$

Whakaoti mō x

$$\left\{\begin{matrix}x=\frac{3+2f-y}{f}\text{, }&f\neq 0\\x\in \mathrm{R}\text{, }&y=3\text{ and }f=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{1}{2}f ki te 2x-4.

$$y-3=-fx+2f$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-fx+2f=y-3$$

Tangohia te 2f mai i ngā taha e rua.

$$-fx=y-3-2f$$

He hanga arowhānui tō te whārite.

$$\left(-f\right)x=y-2f-3$$

Whakawehea ngā taha e rua ki te -f.

$$\frac{\left(-f\right)x}{-f}=\frac{y-2f-3}{-f}$$

Mā te whakawehe ki te -f ka wetekia te whakareanga ki te -f.

$$x=\frac{y-2f-3}{-f}$$

Whakawehe y-2f-3 ki te -f.

$$x=-\frac{y-2f-3}{f}$$