Whakaoti i te y-1/8=-1/8x

$$y - \frac { 1 } { 8 } = \frac { - 1 } { 8 } x$$

Whakaoti mō x

$$x=1-8y$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Ka taea te hautanga \frac{-1}{8} te tuhi anō ko -\frac{1}{8} mā te tango i te tohu tōraro.

$$y-\frac{1}{8}=-\frac{1}{8}x$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-\frac{1}{8}x=y-\frac{1}{8}$$

Me whakarea ngā taha e rua ki te -8.

$$\frac{-\frac{1}{8}x}{-\frac{1}{8}}=\frac{y-\frac{1}{8}}{-\frac{1}{8}}$$

Mā te whakawehe ki te -\frac{1}{8} ka wetekia te whakareanga ki te -\frac{1}{8}.

$$x=\frac{y-\frac{1}{8}}{-\frac{1}{8}}$$

Whakawehe y-\frac{1}{8} ki te -\frac{1}{8} mā te whakarea y-\frac{1}{8} ki te tau huripoki o -\frac{1}{8}.

$$x=1-8y$$

Whakaoti mō y

$$y=\frac{1-x}{8}$$

Ngā Upane Otinga

Ka taea te hautanga \frac{-1}{8} te tuhi anō ko -\frac{1}{8} mā te tango i te tohu tōraro.

$$y-\frac{1}{8}=-\frac{1}{8}x$$

Me tāpiri te \frac{1}{8} ki ngā taha e rua.

$$y=-\frac{1}{8}x+\frac{1}{8}$$