Whakaoti i te y(3-2x)-x=4(1-3x)+2

$$y ( 3 - 2 x ) - x = 4 ( 1 - 3 x ) + 2$$

Whakaoti mō x

$$x=-\frac{3\left(y-2\right)}{11-2y}$$

$$y\neq \frac{11}{2}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te y ki te 3-2x.

$$3y-2yx-x=4\left(1-3x\right)+2$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te 1-3x.

$$3y-2yx-x=4-12x+2$$

Tāpirihia te 4 ki te 2, ka 6.

$$3y-2yx-x=6-12x$$

Me tāpiri te 12x ki ngā taha e rua.

$$3y-2yx-x+12x=6$$

Pahekotia te -x me 12x, ka 11x.

$$3y-2yx+11x=6$$

Tangohia te 3y mai i ngā taha e rua.

$$-2yx+11x=6-3y$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(-2y+11\right)x=6-3y$$

He hanga arowhānui tō te whārite.

$$\left(11-2y\right)x=6-3y$$

Whakawehea ngā taha e rua ki te -2y+11.

$$\frac{\left(11-2y\right)x}{11-2y}=\frac{6-3y}{11-2y}$$

Mā te whakawehe ki te -2y+11 ka wetekia te whakareanga ki te -2y+11.

$$x=\frac{6-3y}{11-2y}$$

Whakawehe 6-3y ki te -2y+11.

$$x=\frac{3\left(2-y\right)}{11-2y}$$

Whakaoti mō y

$$y=-\frac{11x-6}{3-2x}$$

$$x\neq \frac{3}{2}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te y ki te 3-2x.

$$3y-2yx-x=4\left(1-3x\right)+2$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te 1-3x.

$$3y-2yx-x=4-12x+2$$

Tāpirihia te 4 ki te 2, ka 6.

$$3y-2yx-x=6-12x$$

Me tāpiri te x ki ngā taha e rua.

$$3y-2yx=6-12x+x$$

Pahekotia te -12x me x, ka -11x.

$$3y-2yx=6-11x$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(3-2x\right)y=6-11x$$

Whakawehea ngā taha e rua ki te 3-2x.

$$\frac{\left(3-2x\right)y}{3-2x}=\frac{6-11x}{3-2x}$$

Mā te whakawehe ki te 3-2x ka wetekia te whakareanga ki te 3-2x.

$$y=\frac{6-11x}{3-2x}$$