Whakaoti i te y^2-8y-8x+8=0

$$y ^ { 2 } - 8 y - 8 x + 8 = 0$$

Whakaoti mō x

$$x=\frac{y^{2}-8y+8}{8}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te y^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-8y-8x+8=-y^{2}$$

Me tāpiri te 8y ki ngā taha e rua.

$$-8x+8=-y^{2}+8y$$

Tangohia te 8 mai i ngā taha e rua.

$$-8x=-y^{2}+8y-8$$

Whakawehea ngā taha e rua ki te -8.

$$\frac{-8x}{-8}=\frac{-y^{2}+8y-8}{-8}$$

Mā te whakawehe ki te -8 ka wetekia te whakareanga ki te -8.

$$x=\frac{-y^{2}+8y-8}{-8}$$

Whakawehe -y^{2}+8y-8 ki te -8.

$$x=\frac{y^{2}}{8}-y+1$$

Whakaoti mō y (complex solution)

$$y=2\sqrt{2x+2}+4$$

$$y=-2\sqrt{2x+2}+4$$

Whakaoti mō y

$$y=2\sqrt{2x+2}+4$$

$$y=-2\sqrt{2x+2}+4\text{, }x\geq -1$$