Whakaoti i te y^2-8x+6y+1=0

$$y ^ { 2 } - 8 x + 6 y + 1 = 0$$

Whakaoti mō x

$$x=\frac{y^{2}+6y+1}{8}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te y^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-8x+6y+1=-y^{2}$$

Tangohia te 6y mai i ngā taha e rua.

$$-8x+1=-y^{2}-6y$$

Tangohia te 1 mai i ngā taha e rua.

$$-8x=-y^{2}-6y-1$$

Whakawehea ngā taha e rua ki te -8.

$$\frac{-8x}{-8}=\frac{-y^{2}-6y-1}{-8}$$

Mā te whakawehe ki te -8 ka wetekia te whakareanga ki te -8.

$$x=\frac{-y^{2}-6y-1}{-8}$$

Whakawehe -y^{2}-6y-1 ki te -8.

$$x=\frac{y^{2}}{8}+\frac{3y}{4}+\frac{1}{8}$$

Whakaoti mō y (complex solution)

$$y=2\sqrt{2\left(x+1\right)}-3$$

$$y=-2\sqrt{2\left(x+1\right)}-3$$

Whakaoti mō y

$$y=2\sqrt{2\left(x+1\right)}-3$$

$$y=-2\sqrt{2\left(x+1\right)}-3\text{, }x\geq -1$$