Whakaoti i te y^2=52-48*(-08)

$$y ^ { 2 } = 52 - 48 \cdot ( - 08 )$$

Whakaoti mō y

$$y=2\sqrt{13}\approx 7.211102551$$

$$y=-2\sqrt{13}\approx -7.211102551$$

Ngā Upane mā te Kimi Pūtakerua

Whakareatia te 48 ki te 0, ka 0.

$$y^{2}=52-0\times 8$$

Whakareatia te 0 ki te 8, ka 0.

$$y^{2}=52-0$$

Tangohia te 0 i te 52, ka 52.

$$y^{2}=52$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$y=2\sqrt{13} y=-2\sqrt{13}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te 48 ki te 0, ka 0.

$$y^{2}=52-0\times 8$$

Whakareatia te 0 ki te 8, ka 0.

$$y^{2}=52-0$$

Tangohia te 0 i te 52, ka 52.

$$y^{2}=52$$

Tangohia te 52 mai i ngā taha e rua.

$$y^{2}-52=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -52 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\left(-52\right)}}{2}$$

Pūrua 0.

$$y=\frac{0±\sqrt{-4\left(-52\right)}}{2}$$

Whakareatia -4 ki te -52.

$$y=\frac{0±\sqrt{208}}{2}$$

Tuhia te pūtakerua o te 208.

$$y=\frac{0±4\sqrt{13}}{2}$$

Nā, me whakaoti te whārite y=\frac{0±4\sqrt{13}}{2} ina he tāpiri te ±.

$$y=2\sqrt{13}$$

Nā, me whakaoti te whārite y=\frac{0±4\sqrt{13}}{2} ina he tango te ±.

$$y=-2\sqrt{13}$$

Kua oti te whārite te whakatau.

$$y=2\sqrt{13} y=-2\sqrt{13}$$