Whakaoti i te y^2=52-48*(-0.8)

$$y ^ { 2 } = 52 - 48 \cdot ( - 0.8 )$$

Whakaoti mō y

$$y = \frac{2 \sqrt{565}}{5} \approx 9.507891459$$

$$y = -\frac{2 \sqrt{565}}{5} \approx -9.507891459$$

Ngā Upane mā te Kimi Pūtakerua

Whakareatia te 48 ki te -0.8, ka -38.4.

$$y^{2}=52-\left(-38.4\right)$$

Ko te tauaro o -38.4 ko 38.4.

$$y^{2}=52+38.4$$

Tāpirihia te 52 ki te 38.4, ka 90.4.

$$y^{2}=90.4$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$y=\frac{2\sqrt{565}}{5} y=-\frac{2\sqrt{565}}{5}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te 48 ki te -0.8, ka -38.4.

$$y^{2}=52-\left(-38.4\right)$$

Ko te tauaro o -38.4 ko 38.4.

$$y^{2}=52+38.4$$

Tāpirihia te 52 ki te 38.4, ka 90.4.

$$y^{2}=90.4$$

Tangohia te 90.4 mai i ngā taha e rua.

$$y^{2}-90.4=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -90.4 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\left(-90.4\right)}}{2}$$

Pūrua 0.

$$y=\frac{0±\sqrt{-4\left(-90.4\right)}}{2}$$

Whakareatia -4 ki te -90.4.

$$y=\frac{0±\sqrt{361.6}}{2}$$

Tuhia te pūtakerua o te 361.6.

$$y=\frac{0±\frac{4\sqrt{565}}{5}}{2}$$

Nā, me whakaoti te whārite y=\frac{0±\frac{4\sqrt{565}}{5}}{2} ina he tāpiri te ±.

$$y=\frac{2\sqrt{565}}{5}$$

Nā, me whakaoti te whārite y=\frac{0±\frac{4\sqrt{565}}{5}}{2} ina he tango te ±.

$$y=-\frac{2\sqrt{565}}{5}$$

Kua oti te whārite te whakatau.

$$y=\frac{2\sqrt{565}}{5} y=-\frac{2\sqrt{565}}{5}$$