Whakaoti i te y^2=2/3(x-1)

$$y ^ { 2 } = \frac { 2 } { 3 } ( x - 1 )$$

Whakaoti mō x

$$x=\frac{3y^{2}}{2}+1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{2}{3} ki te x-1.

$$y^{2}=\frac{2}{3}x-\frac{2}{3}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\frac{2}{3}x-\frac{2}{3}=y^{2}$$

Me tāpiri te \frac{2}{3} ki ngā taha e rua.

$$\frac{2}{3}x=y^{2}+\frac{2}{3}$$

Whakawehea ngā taha e rua o te whārite ki te \frac{2}{3}, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$\frac{\frac{2}{3}x}{\frac{2}{3}}=\frac{y^{2}+\frac{2}{3}}{\frac{2}{3}}$$

Mā te whakawehe ki te \frac{2}{3} ka wetekia te whakareanga ki te \frac{2}{3}.

$$x=\frac{y^{2}+\frac{2}{3}}{\frac{2}{3}}$$

Whakawehe y^{2}+\frac{2}{3} ki te \frac{2}{3} mā te whakarea y^{2}+\frac{2}{3} ki te tau huripoki o \frac{2}{3}.

$$x=\frac{3y^{2}}{2}+1$$

Whakaoti mō y (complex solution)

$$y=-\frac{\sqrt{6\left(x-1\right)}}{3}$$

$$y=\frac{\sqrt{6\left(x-1\right)}}{3}$$

Whakaoti mō y

$$y=\frac{\sqrt{6\left(x-1\right)}}{3}$$

$$y=-\frac{\sqrt{6\left(x-1\right)}}{3}\text{, }x\geq 1$$