Whakaoti i te y^2+8y-4x=m

$$y ^ { 2 } + 8 y - 4 x = m$$

Whakaoti mō x

$$x=\frac{y^{2}+8y-m}{4}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te y^{2} mai i ngā taha e rua.

$$8y-4x=m-y^{2}$$

Tangohia te 8y mai i ngā taha e rua.

$$-4x=m-y^{2}-8y$$

He hanga arowhānui tō te whārite.

$$-4x=m-8y-y^{2}$$

Whakawehea ngā taha e rua ki te -4.

$$\frac{-4x}{-4}=\frac{m-8y-y^{2}}{-4}$$

Mā te whakawehe ki te -4 ka wetekia te whakareanga ki te -4.

$$x=\frac{m-8y-y^{2}}{-4}$$

Whakawehe m-y^{2}-8y ki te -4.

$$x=\frac{y^{2}}{4}-\frac{m}{4}+2y$$

Whakaoti mō m

$$m=8y+y^{2}-4x$$

Ngā Upane Otinga

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$m=y^{2}+8y-4x$$