Whakaoti i te y^2+3y

$$y ^ { 2 } + 3 y$$

Tauwehe

$$y\left(y+3\right)$$

Ngā Upane Otinga

Tauwehea te y.

$$y\left(y+3\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$y^{2}+3y=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$y=\frac{-3±\sqrt{3^{2}}}{2}$$

Tuhia te pūtakerua o te 3^{2}.

$$y=\frac{-3±3}{2}$$

Nā, me whakaoti te whārite y=\frac{-3±3}{2} ina he tāpiri te ±. Tāpiri -3 ki te 3.

$$y=\frac{0}{2}$$

Whakawehe 0 ki te 2.

$$y=0$$

Nā, me whakaoti te whārite y=\frac{-3±3}{2} ina he tango te ±. Tango 3 mai i -3.

$$y=-\frac{6}{2}$$

Whakawehe -6 ki te 2.

$$y=-3$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 0 mō te x_{1} me te -3 mō te x_{2}.

$$y^{2}+3y=y\left(y-\left(-3\right)\right)$$

Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.

$$y^{2}+3y=y\left(y+3\right)$$

Aromātai

$$y\left(y+3\right)$$