Whakaoti i te y^2+16y-4x+4=0

$$y ^ { 2 } + 16 y - 4 x + 4 = 0$$

Whakaoti mō x

$$x=\frac{y^{2}+16y+4}{4}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te y^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$16y-4x+4=-y^{2}$$

Tangohia te 16y mai i ngā taha e rua.

$$-4x+4=-y^{2}-16y$$

Tangohia te 4 mai i ngā taha e rua.

$$-4x=-y^{2}-16y-4$$

Whakawehea ngā taha e rua ki te -4.

$$\frac{-4x}{-4}=\frac{-y^{2}-16y-4}{-4}$$

Mā te whakawehe ki te -4 ka wetekia te whakareanga ki te -4.

$$x=\frac{-y^{2}-16y-4}{-4}$$

Whakawehe -y^{2}-16y-4 ki te -4.

$$x=\frac{y^{2}}{4}+4y+1$$

Whakaoti mō y (complex solution)

$$y=2\sqrt{x+15}-8$$

$$y=-2\sqrt{x+15}-8$$

Whakaoti mō y

$$y=2\sqrt{x+15}-8$$

$$y=-2\sqrt{x+15}-8\text{, }x\geq -15$$